@meenachourasia3107
You can also do it like this √3+√3+√3=√3*√3*√3 3√3. =. 3√3 (If we add √3 n numbers of time it will be n√3 and √3*√3 will be 3 then if we multiply remaining √3 with 3 then it will give 3√3 there fore LHS =RHS
@vedantsingh9156
If A+B+C= pie then tanA.tanB.tanC=tanA+tanB+tanC put A=B=C=pie/3
@CubeMasterDignesh
The method used in video is high lvl But there is easy method also like √3+√3+√3 = √3×√3×√3 Here, 3√3 = 3×√3. (As,√3×√3=3) Hence,3√3=3√3 Therefore LHS=RHS Who like it👆👆👇👇
@New1og52
For any integer x and real number k the equation xk = k^x always has x-1th root of x as k as a solution so 4k = k^4 has cube root of 4 has one of the solutions
@tulayersoz4708
a+a+a=a^3 3a=a^3 a^3-3a=0 a(a^2-3)=a(a-root3)(a+root3)=0 a=0,a=root3,a=-root3.
@PrashantSinhghal
Aisa isliye hota ha kyuki triangle mein tanA+tanB+ tanC=tanAtanBtanC Vo equilateral triangle hai every angle 60 deg hota hai isliye yeh baraber hai
@tonnam7338
I like maths. √
@subbulakshmi7610
Salesman is doing math😂😂
@darkjoker_18
Its 3=3 If we divide all the adding /3 by/3 we get 1 and 1+1+1=3
@Fischer_fan
Math= Salesman🤷♂️
@Mysteriousteacher2
Take root 3 common /3(1+1+1)=root 3.3.3 Cut 1 root 3 to root 3 1+1+1=root3.3 3=3 hp
@Parisfcfan1404
Sqrt(3)+ Sqrt(3)+ Sqrt(3)=3 Sqrt(3) Sqrt(3)x Sqrt(3)x Sqrt(3)= Sqrt(3x3)x Sqrt(3)=3 Sqrt(3)
@DimitriNakamoto
3x = x³ x = 0,±√3
@NatiqZeynalli
3√3 (√3)³
(√x)³=√(x³)
x√x=√(x³)
√3³=√27
@SakshamSingh-c2q
Question See it is hard but it is very easy .
@Релайм
3x=x cubed x cubed-3x=0 x=0 x squared-3=0 x squared=3 x=sqrt(3)
@powerwashere5918
√3+√3+√3 = √3×√3×√3
[There are three 1s in front of the square roots, but they're all invisible. The square roots of 3 can be written as (√a × √b = √ab) ]:
Rewritting the term:
1√3+1√3+1√3 = √3×3×3
3√3 = √27 (3³ or 3² x 3 = 27)
3√3 = √3² × 3
3√3 = 3√3
Therefore: 3√3 = 3√3
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@CentaurHeir
Salesman doing math now🔥🔥🔥
@ajmagallano332
Both is just 3√3
@pieceofwaterofficial330